49x^2+49x-603=0

Solution for 49x^2+49x-603=0 equation:

49x^2+49x-603=0

a = 49; b = 49; c = -603;
Δ = b2-4ac
Δ = 492-4·49·(-603)
Δ = 120589
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120589}=\sqrt{49*2461}=\sqrt{49}*\sqrt{2461}=7\sqrt{2461}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-7\sqrt{2461}}{2*49}=\frac{-49-7\sqrt{2461}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+7\sqrt{2461}}{2*49}=\frac{-49+7\sqrt{2461}}{98}
$